Elimination reactions
|
Chapter 5:
Structure and Preparation of Alkenes. Elimination Reactions
|
In order to view some of
the structures for this section, you will need the web "plug-in", "CHIME". If
you do not have it already installed, you should be able to download it for
free from the linked
Website. CHIME is a browser that allows you to visualize and manipulate
molecules as 3D structures. Check here
if you don't know how to use Chime.
Elimination reactions are
important as a method for the preparation of alkenes.
The term "elimination" describes the fact that a small molecule
is lost during the process.
A 1,2-elimination indicates that the atoms that are lost come from adjacent
C atoms.
The two most important methods are:
- Dehydration (-H2O)
of alcohols, and
- Dehydrohalogenation
(-HX) of alkyl halides.
There are three fundamental
events in these elimination reactions:
- removal of a proton
- formation of the CC
p bond
- breaking of the bond
to the leaving group
Depending on the relative timing
of these events, different mechanisms are possible:
- Loss of the LG
to form a carbocation, removal of H+ and formation of C=C
bond : E1 reaction
- Simultaneous H+
removal, C=C bond formation and loss of the LG
: E2 reaction
- Removal of H+
to form a carbanion, loss of the LG and
formation of C=C bond (E1cb reaction)
In many cases the elimination
reaction may proceed to alkenes that are constitutional isomers with one formed
in excess of the other. This is described as regioselectivity.
Zaitsev's
rule, based on the dehydration of alcohols, describes the preference
for eliminations to give the highly substituted (more stable) alkene, which
may also be described as the Zaitsev product. The rule is not always
obeyed, some reactions give the anti-Zaitsev product.
Similarly, eliminations
often favor the more stable trans-product over the cis-product (stereoselectivity)
Carbocations
Stability:
The general stability order of simple alkyl carbocations is: (most stable) 3o
> 2o > 1o > methyl (least stable)
This is because alkyl groups
are weakly electron donating due to hyperconjugation and inductive effects.
Resonance effects can further stabilize carbocations when present.
Structure:
Reactivity:
Rearrangements:
Carbocations are prone to rearrangement via 1,2-hyride or 1,2-alkyl shifts provided
it generates a more stable carbocation. For example:
This is an example of a
1,2-alkyl shift. The numbers indicate that the alkyl group moves
to an adjacent position.
Similar migrations of H atoms, 1,2-hydride shifts are also known.
Reactions
involving carbocations:
1. Substitutions via the SN1
2. Eliminations via the E1
3. Additions to alkenes and alkynes (HX, H3O+)
E1 mechanism
E1 indicates a elimination,
unimolecular reaction, where rate = k [R-LG].
This implies that the rate determining step of the mechanism depends on the
decomposition of a single molecular species.
Overall, this pathway is
a multi-step process with the following two critical steps:
Lets look at how the various
components of the reaction influence the reaction pathway:
R-
Reactivity order : (CH3)3C- >
(CH3)2CH- > CH3CH2-
> CH3-
In an E1 reaction, the rate
determining step is the loss of the leaving group to form the intermediate carbocation.
The more stable the carbocation is, the easier it is to form, and the faster
the E1 reaction will be. Some students fall into the trap of thinking
that the system with the less stable carbocation will react fastest, but they
are forgetting that it is the generation of the carbocation that is rate determining.
Since carbocation intermediates are formed during an E1, there is always
the possibility of rearrangements (e.g. 1,2-hydride or 1,2-alkyl shifts)
to generate a more stable carbocation. This is usually indicated by a change
in the position of the alkene or a change in the carbon skeleton of the product
when compared to the starting material.
-LG
The only event in the rate determining step of the E1 is breaking the C-LG
bond. Therefore, there is a very strong dependence on the nature of the leaving
group, the better the leaving group, the faster the E1 reaction will be.
In the acid catlaysed reactions of alcohols, the -OH is protonated first
to give an oxonium ion, providing the much better leaving group, a water molecule
(see scheme below).
B
Since the base is not involved in the rate determining step, the nature of the
base is unimportant in an E1 reaction. However, the more reactive the base,
the more likely an E2 reaction becomes.
Selectivity
E1 reactions usually favor the more stable alkene as the major product : more
highly substituted and trans- > cis-
This E1 mechanistic pathway
is most common with:
- good leaving groups
- stable carbocations
- weak bases.
A typical example is the acid
catalyzed dehydration of 2o or 3o alcohols.
Carbocations
Stability:
The general stability order of simple alkyl carbocations is: (most stable) 3o
> 2o > 1o > methyl (least stable)
This is because alkyl groups
are weakly electron donating due to hyperconjugation and inductive effects.
Resonance effects can further stabilize carbocations when present.
Structure:
Reactivity:
Rearrangements:
Carbocations are prone to rearrangement via 1,2-hyride or 1,2-alkyl shifts provided
it generates a more stable carbocation. For example:
This is an example of a
1,2-alkyl shift. The numbers indicate that the alkyl group moves
to an adjacent position.
Similar migrations of H atoms, 1,2-hydride shifts are also known.
Reactions
involving carbocations:
1. Substitutions via the SN1
2. Eliminations via the E1
3. Additions to alkenes and alkynes (HX, H3O+)
E2 mechanism
E2 indicates an elimination,
bimolecular reaction, where rate = k [B][R-LG].
This implies that the rate determining step involves an interaction between
these two species, the base and the organic substrate.
This pathway is a concerted
process with the following characteristics:
Simultaneous removal of the proton, H+, by the base, loss of the
leaving group, LG, and formation of the
p- bond
Let's look at how the various
components of the reaction influence the reaction pathway:
Effects of R-
In an E2 reaction, the reaction transforms 2 sp3 C atoms into sp2
C atoms. This moves the substituents further apart decreasing any steric interactions.
So more highly substituted systems undergo E2 eliminations more rapidly. This
is the same reactivity trend as seen in E1 reactions.
-LG
The C-LG bond is broken during the rate
determining step, so the rate does depend on the nature of the leaving group.
However, if a leaving group is too good, then an E1 reaction may result.
B
Since the base is involved in the rate determining step, the nature of the base
is very important in an E2 reaction. More reactive bases will favor an E2 reaction.
Stereochemistry
E2 reactions occur most rapidly when the H-C
bond and C-LG bonds involved are
co-planar, most often at 180o or antiperiplanar. This conformation
postitions the s bonds that are broken in the correct alignment to become the
p bond. More
details ?
Selectivity
The outcome of E2 reactions is controlled by the stereochemical requirements
described above. Where there is a choice, the more stable alkene will be the
major product.
The E2 pathway is most common
with:
- high concentration of
a strong base
- poorer leaving groups
- R-LG
that would not lead to stable carbocations (when the E1 mechanism will
occur).
A typical example is the dehydrohalogenation
of alkyl halides using KOtBu / tBuOH.
E2 Stereochemistry
E2 reactions occur most
rapidly when the H-C bond and C-LG
bonds involved are co-planar, most often at 180o with respect to
each other. This is described as an antiperiplanar conformation. This
conformation positions the s bonds that are being broken in the correct alignment
to become the p bond.
Synperiplanar arrangments
where the angle between the H-C bond
and C-LG is 0o are also
known, usually in systems that are either inflexible rings or intramolecular
eliminations.
These alignments are examples
of a stereoelectronic effect because they involve the specific spatial
postioning of the bonds (electrons) in order for the process to occur.
Implications:
|
The cis-
isomer undergoes elimination over 500 times faster than the trans- isomer.
In the cyclic system,
in order for the preferred antiperiplanar arrangement favored by E2
reactions, the C-H and C-LG
bonds both need to be axial.
|
Recall that in chapter 3
that we learned that the t-butyl group has a strong preference for the equatorial
position on cyclohexanes and acts as a "lock". In the trans isomer, this means
that the -Br is also equatorial and is therefore
anti to C-C bonds, not C-H. Since
the cyclohexane is locked it cannot ring flip into the geometry required for
the E2 and elimination is slow.
In contrast, in the cis isomer, the -Br
is axial and is anti to 2 C-H
bonds and the E2 occurs rapidly. Use the CHIME images below to show the antiperiplanar
bonds if you need to.
Selectivity
In many cases elimination
reactions may proceed to alkenes that are isomeric but with one formed in excess
of the other.
Regioselectivity
(products are constitutional isomers):
Zaitsev's rule, based
on experiment observations of the dehydration of alcohols, expresses the
preference for eliminations to give the highly substituted (more stable)
alkene, which may also be described as the Zaitsev product.
The rule is not always obeyed, some reactions give the anti-Zaitsev product
which is sometimes described as the Hoffman product. (Hoffman studied the elimination
of ammonium salts)
Care is needed with E2 eliminations of cyclic systems since the antiperiplanar
alignment of the C-H and C-LG bonds
can dictate that the anti-Zaitsev products dominate.
Stereoselectivity (products
are stereoisomers)
Similarly, eliminations often
favor the more stable trans-product over the cis-product.
Help
with chime files
Elimination reactions
|
Chapter 5:
Structure and Preparation of Alkenes. Elimination Reactions
|
In order to view some of
the structures for this section, you will need the web "plug-in", "CHIME". If
you do not have it already installed, you should be able to download it for
free from the linked
Website. CHIME is a browser that allows you to visualize and manipulate
molecules as 3D structures. Check here
if you don't know how to use Chime.
Elimination reactions are
important as a method for the preparation of alkenes.
The term "elimination" describes the fact that a small molecule
is lost during the process.
A 1,2-elimination indicates that the atoms that are lost come from adjacent
C atoms.
The two most important methods are:
- Dehydration (-H2O)
of alcohols, and
- Dehydrohalogenation
(-HX) of alkyl halides.
There are three fundamental
events in these elimination reactions:
- removal of a proton
- formation of the CC
p bond
- breaking of the bond
to the leaving group
Depending on the relative timing
of these events, different mechanisms are possible:
- Loss of the LG
to form a carbocation, removal of H+ and formation of C=C
bond : E1 reaction
- Simultaneous H+
removal, C=C bond formation and loss of the LG
: E2 reaction
- Removal of H+
to form a carbanion, loss of the LG and
formation of C=C bond (E1cb reaction)
In many cases the elimination
reaction may proceed to alkenes that are constitutional isomers with one formed
in excess of the other. This is described as regioselectivity.
Zaitsev's
rule, based on the dehydration of alcohols, describes the preference
for eliminations to give the highly substituted (more stable) alkene, which
may also be described as the Zaitsev product. The rule is not always
obeyed, some reactions give the anti-Zaitsev product.
Similarly, eliminations
often favor the more stable trans-product over the cis-product (stereoselectivity)
Carbocations
Stability:
The general stability order of simple alkyl carbocations is: (most stable) 3o
> 2o > 1o > methyl (least stable)
This is because alkyl groups
are weakly electron donating due to hyperconjugation and inductive effects.
Resonance effects can further stabilize carbocations when present.
Structure:
Reactivity:
Rearrangements:
Carbocations are prone to rearrangement via 1,2-hyride or 1,2-alkyl shifts provided
it generates a more stable carbocation. For example:
This is an example of a
1,2-alkyl shift. The numbers indicate that the alkyl group moves
to an adjacent position.
Similar migrations of H atoms, 1,2-hydride shifts are also known.
Reactions
involving carbocations:
1. Substitutions via the SN1
2. Eliminations via the E1
3. Additions to alkenes and alkynes (HX, H3O+)
E1 mechanism
E1 indicates a elimination,
unimolecular reaction, where rate = k [R-LG].
This implies that the rate determining step of the mechanism depends on the
decomposition of a single molecular species.
Overall, this pathway is
a multi-step process with the following two critical steps:
Lets look at how the various
components of the reaction influence the reaction pathway:
R-
Reactivity order : (CH3)3C- >
(CH3)2CH- > CH3CH2-
> CH3-
In an E1 reaction, the rate
determining step is the loss of the leaving group to form the intermediate carbocation.
The more stable the carbocation is, the easier it is to form, and the faster
the E1 reaction will be. Some students fall into the trap of thinking
that the system with the less stable carbocation will react fastest, but they
are forgetting that it is the generation of the carbocation that is rate determining.
Since carbocation intermediates are formed during an E1, there is always
the possibility of rearrangements (e.g. 1,2-hydride or 1,2-alkyl shifts)
to generate a more stable carbocation. This is usually indicated by a change
in the position of the alkene or a change in the carbon skeleton of the product
when compared to the starting material.
-LG
The only event in the rate determining step of the E1 is breaking the C-LG
bond. Therefore, there is a very strong dependence on the nature of the leaving
group, the better the leaving group, the faster the E1 reaction will be.
In the acid catlaysed reactions of alcohols, the -OH is protonated first
to give an oxonium ion, providing the much better leaving group, a water molecule
(see scheme below).
B
Since the base is not involved in the rate determining step, the nature of the
base is unimportant in an E1 reaction. However, the more reactive the base,
the more likely an E2 reaction becomes.
Selectivity
E1 reactions usually favor the more stable alkene as the major product : more
highly substituted and trans- > cis-
This E1 mechanistic pathway
is most common with:
- good leaving groups
- stable carbocations
- weak bases.
A typical example is the acid
catalyzed dehydration of 2o or 3o alcohols.
Carbocations
Stability:
The general stability order of simple alkyl carbocations is: (most stable) 3o
> 2o > 1o > methyl (least stable)
This is because alkyl groups
are weakly electron donating due to hyperconjugation and inductive effects.
Resonance effects can further stabilize carbocations when present.
Structure:
Reactivity:
Rearrangements:
Carbocations are prone to rearrangement via 1,2-hyride or 1,2-alkyl shifts provided
it generates a more stable carbocation. For example:
This is an example of a
1,2-alkyl shift. The numbers indicate that the alkyl group moves
to an adjacent position.
Similar migrations of H atoms, 1,2-hydride shifts are also known.
Reactions
involving carbocations:
1. Substitutions via the SN1
2. Eliminations via the E1
3. Additions to alkenes and alkynes (HX, H3O+)
E2 mechanism
E2 indicates an elimination,
bimolecular reaction, where rate = k [B][R-LG].
This implies that the rate determining step involves an interaction between
these two species, the base and the organic substrate.
This pathway is a concerted
process with the following characteristics:
Simultaneous removal of the proton, H+, by the base, loss of the
leaving group, LG, and formation of the
p- bond
Let's look at how the various
components of the reaction influence the reaction pathway:
Effects of R-
In an E2 reaction, the reaction transforms 2 sp3 C atoms into sp2
C atoms. This moves the substituents further apart decreasing any steric interactions.
So more highly substituted systems undergo E2 eliminations more rapidly. This
is the same reactivity trend as seen in E1 reactions.
-LG
The C-LG bond is broken during the rate
determining step, so the rate does depend on the nature of the leaving group.
However, if a leaving group is too good, then an E1 reaction may result.
B
Since the base is involved in the rate determining step, the nature of the base
is very important in an E2 reaction. More reactive bases will favor an E2 reaction.
Stereochemistry
E2 reactions occur most rapidly when the H-C
bond and C-LG bonds involved are
co-planar, most often at 180o or antiperiplanar. This conformation
postitions the s bonds that are broken in the correct alignment to become the
p bond. More
details ?
Selectivity
The outcome of E2 reactions is controlled by the stereochemical requirements
described above. Where there is a choice, the more stable alkene will be the
major product.
The E2 pathway is most common
with:
- high concentration of
a strong base
- poorer leaving groups
- R-LG
that would not lead to stable carbocations (when the E1 mechanism will
occur).
A typical example is the dehydrohalogenation
of alkyl halides using KOtBu / tBuOH.
E2 Stereochemistry
E2 reactions occur most
rapidly when the H-C bond and C-LG
bonds involved are co-planar, most often at 180o with respect to
each other. This is described as an antiperiplanar conformation. This
conformation positions the s bonds that are being broken in the correct alignment
to become the p bond.
Synperiplanar arrangments
where the angle between the H-C bond
and C-LG is 0o are also
known, usually in systems that are either inflexible rings or intramolecular
eliminations.
These alignments are examples
of a stereoelectronic effect because they involve the specific spatial
postioning of the bonds (electrons) in order for the process to occur.
Implications:
|
The cis-
isomer undergoes elimination over 500 times faster than the trans- isomer.
In the cyclic system,
in order for the preferred antiperiplanar arrangement favored by E2
reactions, the C-H and C-LG
bonds both need to be axial.
|
Recall that in chapter 3
that we learned that the t-butyl group has a strong preference for the equatorial
position on cyclohexanes and acts as a "lock". In the trans isomer, this means
that the -Br is also equatorial and is therefore
anti to C-C bonds, not C-H. Since
the cyclohexane is locked it cannot ring flip into the geometry required for
the E2 and elimination is slow.
In contrast, in the cis isomer, the -Br
is axial and is anti to 2 C-H
bonds and the E2 occurs rapidly. Use the CHIME images below to show the antiperiplanar
bonds if you need to.
Selectivity
In many cases elimination
reactions may proceed to alkenes that are isomeric but with one formed in excess
of the other.
Regioselectivity
(products are constitutional isomers):
Zaitsev's rule, based
on experiment observations of the dehydration of alcohols, expresses the
preference for eliminations to give the highly substituted (more stable)
alkene, which may also be described as the Zaitsev product.
The rule is not always obeyed, some reactions give the anti-Zaitsev product
which is sometimes described as the Hoffman product. (Hoffman studied the elimination
of ammonium salts)
Care is needed with E2 eliminations of cyclic systems since the antiperiplanar
alignment of the C-H and C-LG bonds
can dictate that the anti-Zaitsev products dominate.
Stereoselectivity (products
are stereoisomers)
Similarly, eliminations often
favor the more stable trans-product over the cis-product.
Help
with chime files